# Statistics

A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of \$26 per week with a standard deviation of \$8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per week.

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1. 26-2.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)),

= ( , ) ?

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posted by Kuai
2. That's what I originally did but it's not one of the correct answers

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posted by Cam
3. [ 23.37, 28.63]

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posted by Kuai
4. \$9,531 to \$11,269

\$9,347 to \$11,453

\$10,028 to \$10,772

\$9,414 to \$11,386

Are my multiple choice

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posted by Cam
5. mean 26(400) = \$10400

Standard deviation = 8(400) = 3200
10400-+ 2.3263*3200/sqrt(50))

[\$9,347, 11,453]

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posted by Kuai
6. Thank you so much !

1. 0
posted by Cam

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