a 36 kg child slides down a slide at a height of 2.5 m at at velocity of 3 m/s. how much energy was transferred by friction as she slid down the slide?
efas
To calculate the amount of energy transferred by friction, we need to find the difference in potential energy and kinetic energy of the child as she slides down the slide.
First, let's calculate the potential energy (PE) of the child at the top of the slide using the formula:
PE = m * g * h
where m is the mass (36 kg), g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the slide (2.5 m).
PE = 36 kg * 9.8 m/s^2 * 2.5 m
PE = 882 J (Joules)
Next, let's calculate the kinetic energy (KE) of the child at the bottom of the slide using the formula:
KE = (1/2) * m * v^2
where v is the velocity of the child (3 m/s).
KE = 0.5 * 36 kg * (3 m/s)^2
KE = 162 J (Joules)
Finally, to find the energy transferred by friction, we can subtract the kinetic energy from the potential energy:
Energy transferred by friction = PE - KE
Energy transferred by friction = 882 J - 162 J
Energy transferred by friction = 720 J (Joules)
Hence, the energy transferred by friction as the child slid down the slide was 720 Joules.