An object in simple harmonic motion has an amplitude of 0.202 m and an oscillation period of 0.620 s. Determine the maximum speed of the motion
To determine the maximum speed of an object in simple harmonic motion, we need to know its amplitude and period. The maximum speed occurs when the object is at the equilibrium position.
The formula to calculate the maximum speed, also known as the amplitude of velocity, v_max, in simple harmonic motion is given by:
v_max = 2πA / T
Where:
- v_max is the maximum speed
- A is the amplitude of the motion
- T is the period of the motion
Given:
Amplitude, A = 0.202 m
Oscillation Period, T = 0.620 s
We can now substitute these values into the formula to calculate the maximum speed:
v_max = 2π * 0.202 / 0.620
Calculating further, we have:
v_max = 1.294 m/s
Therefore, the maximum speed of the object in simple harmonic motion is approximately 1.294 m/s.