Given the equation of the circle (x – 9)2 + y2 = 484 , where is the center of the circle located at?
centre is at (9,0), radius = √484 or 22
(use ^ to indicate an exponent such as
(x-9)^2 + y^2 = 484
Which equation can be used to find the volume of a sphere that has a radius of 9 inches
To find the center of a circle given its equation, we need to rewrite the equation in a standard form: (x - h)^2 + (y - k)^2 = r^2.
In this case, the equation of the circle is (x - 9)^2 + y^2 = 484.
Comparing this with the standard form, we can see that:
- (x - h)^2 corresponds to (x - 9)^2, meaning h = 9.
- (y - k)^2 corresponds to y^2, meaning k = 0.
So, the center of the circle is located at the point (h, k) = (9, 0).