a bullet of mass 0.04kg moving with a speed of 90m/s enter a heavy wooden block is stopped after a distance of 60cm.What is the avg resistive force exertes by the block or the bullet
KE=W(resistive force)
mv²/2 = Fs
F= mv²/2s
To find the average resistive force exerted by the block on the bullet, we can use the principle of conservation of momentum.
The equation for momentum is given by:
Momentum = mass x velocity
Since the bullet comes to a stop inside the block, the final velocity of the bullet is 0 m/s. Therefore, using the principle of conservation of momentum, we can calculate the initial velocity of the block:
Momentum before collision = Momentum after collision
(mass of bullet x initial velocity of bullet) = (mass of block x final velocity of block)
(0.04 kg x 90 m/s) = (mass of block x 0 m/s)
0.04 kg x 90 m/s = 0 kg x 0 m/s
3.6 kg⋅m/s = 0 kg⋅m/s
Since the initial velocity of the block is 0 m/s, we can conclude that the block remains at rest. Therefore, there is no resistive force exerted by the block on the bullet.