2(w+18+W)=2(w+18−6+w+3)
perimeter is 126
my teacher ask to get the value of W
assuming that W is the same as w, we have
2(w+18+W)=2(w+18−6+w+3)
2w+36+2w = 2w+36-12+2w+6
0 = -6
Bzzzt
No value of w makes the equation true
Since you're talking perimeter, shouldn't there be a length or something involved?
I think the problem is garbled.
To solve for the value of W, we need to simplify the given equation and isolate the variable.
Let's simplify the equation step by step:
2(w + 18 + W) = 2(w + 18 - 6 + w + 3)
First, simplify the expressions within the parentheses:
2(w + W + 18) = 2(w + w + 18 - 6 + 3)
Next, simplify the expressions within the parentheses further:
2(2w + 18) = 2(2w + 15)
Now, distribute the 2 to the terms within the parentheses:
4w + 36 = 4w + 30
At this point, we notice that the equation contains like terms canceled out on both sides. This means that the equation does not depend on the value of W and is always true.
Since there is no dependency on W, it means that any value of W will give us a true statement. Therefore, the value of W can be any real number.
Hence, we cannot determine a specific value for W based on the given equation.