find the product
v^2+v-12/5v+10*-v-2/v^2+5v+4
product implies that you are multiplying
I see only one multiplication.
Please retype your question using brackets so we can tell what order of operation you want.
I have a feeling you want it to look like
[(v^2 + v - 12)/(5v+10)][(-v-2)/(v^2 + 5v + 4)]
if so then it would factor to:
(v+4)(v-3)/(5(v+2)) * (-1)(v+2)/((v+1)(v+4))
= -(v-3)/(5(v+1)), v not equal to -2,-4
3pq-18pqr
To find the product of the given expression, we will multiply the two fractions together.
First, let's simplify the expressions inside each fraction:
For the first fraction:
Numerator: v^2 + v - 12
This expression cannot be factored further.
Denominator: 5v + 10
Both terms have a common factor of 5, so we can factor that out:
5(v + 2)
For the second fraction:
Numerator: -v - 2
This expression cannot be factored further.
Denominator: v^2 + 5v + 4
This quadratic expression can be factored as (v + 1)(v + 4).
Now, we can rewrite the expression in factored form:
(v^2 + v - 12) / (5v + 10) * (-v - 2) / (v^2 + 5v + 4)
= [(v - 3)(v + 4)] / [5(v + 2)] * [-(v + 2)] / [(v + 1)(v + 4)]
Next, we can cancel out common factors between the numerators and denominators:
= [(v - 3) * -1] / [5(v + 1)]
= -(v - 3) / (5v + 5)
= -v + 3 / 5v + 5
Therefore, the product of the given expression is (-v + 3) / (5v + 5).