For the following chemical reaction write the net ionic equation, including the phases.
2HBr (aq) +Ba(OH)2(aq) --> 2H2O(l) +BaBr2 (aq)
First separate into ions where appropriate following these rules.
1. If aq write ions if strong electrolyte; as molecule if not.
2. Write as molecule if gas
3. Write as molecule if pure liquid
4. Write as molecule if solid.
2H^+(aq) + 2Br^-(aq) + Ba^2+(aq) + 2OH^-(aq) ==> 2H2O(l) + Ba^2+(aq) + 2Br^-(aq)
Now to turn the complete ionic equation into the net ionic equation just cancel the ions common to each side. The net ionic equation is what is left.
I see Br^- on both sides. I see Ba^2+ on both sides. Cancel those on both sides. That leaves you with
2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)
Sure! To write the net ionic equation, we need to start by writing down the balanced chemical equation.
The given balanced chemical equation is:
2HBr (aq) + Ba(OH)2 (aq) → 2H2O (l) + BaBr2 (aq)
To write the net ionic equation, we need to identify the spectator ions. These are the ions that appear on both sides of the equation without undergoing any change. In this case, the spectators are the Ba2+ and OH- ions.
Next, we remove the spectator ions from the equation to obtain the net ionic equation:
2H+ (aq) + 2Br- (aq) → 2H2O (l) + Ba2+ (aq)
So, the net ionic equation for the given chemical reaction is:
2H+ (aq) + 2Br- (aq) → 2H2O (l) + Ba2+ (aq)
The phases for the substances are:
HBr (aq) - aqueous solution
Ba(OH)2 (aq) - aqueous solution
H2O (l) - liquid
BaBr2 (aq) - aqueous solution
To write the net ionic equation for the given chemical reaction, we need to first write the balanced equation.
The balanced equation for the reaction is:
2HBr (aq) + Ba(OH)2 (aq) → 2H2O (l) + BaBr2 (aq)
In order to write the net ionic equation, we need to identify the spectator ions, which are the ions that remain unchanged throughout the reaction.
In this case, the spectator ion is Ba2+.
Taking out the spectator ions, we can write the net ionic equation as:
2H+ (aq) + 2Br- (aq) → 2H2O (l) + Ba2+ (aq)
So, the net ionic equation for the given reaction, including the phases, is:
2H+ (aq) + 2Br- (aq) → 2H2O (l) + Ba2+ (aq)