Consider two charges Q and q separated by a distance d . If the potential at the point p (which is in right side from both charges) is V=0 , we can conclude (one answer only):

a)no net force would act on a test charge located at P .
b)Q and q must be same sign but different magnitude.
c)the net work required to move a third charge from inifinity to point P is zero
d)Electric field at P is zero.
e)none of the above.

To determine the correct answer, we can use the concept of electric potential and the relationship between electric potential and electric field.

The electric potential (V) at a point in an electric field is determined by the work done per unit charge to move the charge from infinity to that point. Mathematically, it is given by V = W/q, where W is the work done and q is the test charge.

In this scenario, the electric potential at point P is given as V = 0. This means that no work is done to move the test charge from infinity to point P. Therefore, we can conclude that the correct answer is:

c) the net work required to move a third charge from infinity to point P is zero.

This indicates that the electric potential at point P is at the same potential as at infinity, and there is no net force acting on a test charge located at point P. The electric field at point P can be non-zero since it depends on the distance and magnitudes of the charges Q and q, but the potential difference V at that point is zero.