it is now 8:59am but when the bell rings at 9:00am Suzete will be late for Science class. She must get from one side of school down three different hallways. She runs down the first a distance of 35.0 m at a speed of 3.50m/s. The second haallway is filled with students and she covers its 48.0 m lenght at an average speed of 1.20m/s. The final hallway is empty and She sprigs its 60.0 m at a speed of 5.00m/s.
determine if shee makes it to calls on time by finding how many seconds she arrives before or after the bell????
distance = rate x time
35.0m = 3.50 m/s x time
Solve for time
Do the same for the other three halls and add the seconds (time) together to find total time. Add that to starting time to determine if she is early, on time, or late.
To determine if Suzete makes it to class on time, we need to calculate the total time it takes for her to travel through each hallway and compare it with the time remaining until 9:00 am.
First, let's calculate the time it takes for Suzete to run down the first hallway:
Distance of the first hallway (d1) = 35.0 m
Speed in the first hallway (v1) = 3.50 m/s
Using the formula: time = distance / speed
Time taken in the first hallway (t1) = d1 / v1 = 35.0 m / 3.50 m/s = 10 seconds
Next, let's calculate the time it takes for Suzete to navigate through the second hallway:
Distance of the second hallway (d2) = 48.0 m
Average speed in the second hallway (v2) = 1.20 m/s
Time taken in the second hallway (t2) = d2 / v2 = 48.0 m / 1.20 m/s = 40 seconds
Lastly, let's calculate the time it takes for Suzete to sprint through the final hallway:
Distance of the final hallway (d3) = 60.0 m
Speed in the final hallway (v3) = 5.00 m/s
Time taken in the final hallway (t3) = d3 / v3 = 60.0 m / 5.00 m/s = 12 seconds
Now, let's add up the times taken for each hallway to get the total time:
Total time taken (total_t) = t1 + t2 + t3 = 10 s + 40 s + 12 s = 62 seconds
Since the current time is 8:59 am, Suzete needs to arrive at class before 9:00 am. She arrives 62 seconds before the bell, which is more than enough time to reach class on time.
Therefore, Suzete will make it to her Science class on time.