last season a little league baseball team traveled a total of 133 miles. For their first game they traveled 16 2/3 miles; second game 2 1/6; third game 25 4/9; and their fourth game 32 1/3. How many miles did they travel for their final fifth away game?
when I add it, all I get are fractions
The common denominator is 18
16 2/3 = 16 12/18
2 1/6 = 2 3/18
25 4/9 = 25 8/18
32 1/3 = 32 6/18
Added together they equal 75 29/18 = 76 11/18
133 = 132 18/18
Now subtract.
132 18/18 - 76 11/18 = 56 7/18 miles
To find the total distance traveled for the first four games, we need to add the distances together. However, since the distances are given in mixed fractions, it might be easier to convert them to improper fractions first.
Let's convert each mixed fraction to an improper fraction:
- The distance traveled for the first game is already in the form of an improper fraction: 16 2/3 = (16 * 3 + 2) / 3 = 50/3.
- The distance for the second game is 2 1/6 = (2 * 6 + 1) / 6 = 13/6.
- The distance for the third game is 25 4/9 = (25 * 9 + 4) / 9 = 229/9.
- The distance for the fourth game is 32 1/3 = (32 * 3 + 1) / 3 = 97/3.
Now let's add these fractions:
50/3 + 13/6 + 229/9 + 97/3
To add these fractions, we need to find a common denominator. The least common multiple (LCM) of 3, 6, and 9 is 18. So, let's rewrite these fractions with a common denominator of 18:
(50/3) x (6/6) = 300/18
(13/6) x (3/3) = 39/18
(229/9) x (2/2) = 458/18
(97/3) x (6/6) = 582/18
Now, let's add the fractions:
300/18 + 39/18 + 458/18 + 582/18 = (300 + 39 + 458 + 582) / 18 = 1379/18
Therefore, the total distance traveled for the first four games is 1379/18 miles.
Since the total distance traveled for the season is 133 miles, we can subtract the total distance for the first four games from this to find the distance traveled for the final fifth away game:
133 - (1379/18) = 2394/18 - 1379/18 = 1015/18
Therefore, the team traveled 1015/18 miles for their final fifth away game.