Calculate the mass in grams of 0.000025 Avagadro's number of rhodium atoms (with the steps please)
I don't understand the problem. What's 0.000025 Avogadro's number of rhodium atoms?
To calculate the mass in grams of 0.000025 Avogadro's number of rhodium atoms, you need to follow these steps:
1. Determine the molar mass of rhodium (Rh):
- The molar mass of rhodium (Rh) is 102.91 g/mol. You can find this value on the periodic table or by searching online.
2. Find the number of atoms:
- Avogadro's number (6.022 x 10^23) represents one mole of any substance.
- So, 0.000025 Avogadro's number represents 0.000025 moles of rhodium atoms.
3. Calculate the number of moles:
- To find the number of moles, use the formula: number of moles = (number of particles) / (Avogadro's number)
- Thus, 0.000025 moles = 0.000025 Avogadro's number / (6.022 x 10^23)
4. Calculate the mass:
- To calculate the mass, use the formula: mass = moles × molar mass
- Therefore, mass = 0.000025 moles × 102.91 g/mol
5. Calculate the result:
- Multiply the number of moles by the molar mass to find the mass of rhodium atoms.
- mass = 0.000025 moles × 102.91 g/mol = 0.00257275 grams
Therefore, the mass in grams of 0.000025 Avogadro's number of rhodium atoms is approximately 0.00257275 grams.