two computer disks and three notebooks cost $17 however, five computer disks an four notebooks cost $32.find the price of each

Let's first assign variables to represent the prices of computer disks and notebooks.

Let's say the price of a computer disk is 'x' dollars, and the price of a notebook is 'y' dollars.

According to the given information, we have two equations:

Equation 1: 2x + 3y = 17 (since two computer disks and three notebooks cost $17)
Equation 2: 5x + 4y = 32 (since five computer disks and four notebooks cost $32)

We can solve this system of equations to find the values of 'x' and 'y'.

Multiplying Equation 1 by 5 and Equation 2 by 2, we get:

10x + 15y = 85
10x + 8y = 64

Now, subtracting Equation 2 from Equation 1:

10x + 15y - (10x + 8y) = 85 - 64
7y = 21

Dividing both sides of the equation by 7:

y = 3

Substituting the value of 'y' in Equation 1:

2x + 3(3) = 17
2x + 9 = 17
2x = 17 - 9
2x = 8
x = 4

Therefore, the price of each computer disk is $4, and the price of each notebook is $3.

Let's assume the price of one computer disk is CD dollars and the price of one notebook is N dollars.

According to the given information, we can set up two equations:

Equation 1: 2CD + 3N = 17 (two computer disks and three notebooks cost $17)
Equation 2: 5CD + 4N = 32 (five computer disks and four notebooks cost $32)

We can now solve these two equations simultaneously to find the values of CD and N.

To solve this system of equations, we can use the method of substitution or elimination.

Method 1: Substitution
First, let's solve Equation 1 for CD and substitute it into Equation 2.

From Equation 1: 2CD + 3N = 17
Solving for CD: 2CD = 17 - 3N
CD = (17 - 3N) / 2

Substituting this value of CD into Equation 2:
5((17 - 3N) / 2) + 4N = 32

Now, we can solve this equation to find the value of N.

Method 2: Elimination
Multiply Equation 1 by 5 and Equation 2 by 2 to eliminate CD:

Equation 3: 10CD + 15N = 85 (multiply Equation 1 by 5)
Equation 4: 10CD + 8N = 64 (multiply Equation 2 by 2)

Subtracting Equation 4 from Equation 3:
(10CD + 15N) - (10CD + 8N) = 85 - 64
7N = 21

Now, we can solve this equation to find the value of N.

Once we find the value of N, we can substitute it back into either Equation 1 or Equation 2 to find the value of CD.

2C+3N=17

5C+4N=32
I assume you can solve that.