The pressure in a 5.75 L container of 48.0 g of bromine gas at 100.0°C is

Assuming the gas is ideal, we can use the Ideal Gas Law:

PV = nRT
where
P = pressure in atm
V = volum in liters
n = number of moles
R = universal gas constant = 0.0821 L-atm/mol-K
T = temperature in Kelvin
We know V, T and of course, R. To convert degree Celsius to Kelvin, we just add 273. To get n, we divide the given mass by the molar mass of bromine. The mass of Br is 79.9, but since it is diatomic (Br2) the molar mass is 79.9 x 2 = 159.8 g/mol
Thus,
n = 48 / 159.8 = 0.300375 mol Br2
Substituting,
PV = nRT
P = nRT / V
P = (0.300375)(0.0821)(100 + 273) / 5.75

Now solve for P. Units are in atm.
Hope this helps :3

1.6

To find the pressure in a container, we need to use the ideal gas law equation:

PV = nRT

Where:
P is the pressure (in Pa or atm)
V is the volume of the container (in L)
n is the number of moles of gas
R is the ideal gas constant (0.0821 L·atm/(mol·K) or 8.314 J/(mol·K))
T is the temperature (in Kelvin)

In this case, we are given the volume (5.75 L), the temperature (100.0°C), and we need to find the pressure. However, we are missing the number of moles of gas (n).

To calculate the number of moles, we use the formula:

n = m/M

Where:
m is the mass of the gas (in grams)
M is the molar mass of the gas (in g/mol)

In this case, we are given the mass of bromine gas (48.0 g). The molar mass of bromine (Br₂) is 159.8 g/mol.

Let's calculate the number of moles:

n = 48.0 g / 159.8 g/mol

n ≈ 0.300 mol

Now that we have the volume (5.75 L), the number of moles (0.300 mol), and the temperature (100.0°C), we can calculate the pressure using the ideal gas law.

First, let's convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15
T(K) = 100.0°C + 273.15
T(K) = 373.15 K

Now, let's substitute the values into the ideal gas law equation:

PV = nRT
P(5.75 L) = (0.300 mol) (0.0821 L·atm/(mol·K)) (373.15 K)

Now we can solve for P:

P = (0.300 mol) (0.0821 L·atm/(mol·K)) (373.15 K) / (5.75 L)

P ≈ 5.13 atm

Therefore, the pressure in the container is approximately 5.13 atm.