How would you put this in an equation in slope intercept form? what would it look like?
Y-intercept -5, X-intercept 3
the slope is 5/3, so
y = 5/3 x - 5
To put the equation in slope-intercept form, we can use the formula: y = mx + b, where "m" represents the slope and "b" represents the y-intercept.
First, let's find the slope of the line using the given information. The slope (m) of the line can be calculated as the change in y divided by the change in x:
m = (y₂ - y₁) / (x₂ - x₁)
The y-intercept is given as -5, which means the point (0, -5) lies on the line.
The x-intercept is given as 3, which means the point (3, 0) lies on the line.
Using these two points, we can calculate the slope:
m = (0 - (-5)) / (3 - 0)
m = 5 / 3
Now that we have the slope (m = 5/3), we can substitute it into the slope-intercept form equation, along with the y-intercept (-5), to write the equation:
y = (5/3)x - 5
So, the equation in slope-intercept form for the given line is y = (5/3)x - 5.