If the distance between two slits is .05mm and the distance to the screen is 2.5m find the spacing between the first and second order bright fringees for yellow light of wavelenght 600nm.

d=5x10^-5m
L=2.5m
wavelength= 6x10^-7m
x=?

x=wavelength*L/d
=(6x10^-7)(2.5)/5x10^-5m
=.03m

I am not sure if this is correct because the part where it states "first and second order bright fringes" confuses me. I am not sure if I am answering the question correctly. Is .03m too big?

You are right. 3 cm.

The formula you used, x = wavelength * L / d, is correct for finding the spacing between adjacent bright fringes in a double-slit experiment.

In this case, wavelength = 6 x 10^-7 m, L = 2.5 m, and d = 5 x 10^-5 m.

By plugging in these values, we have:

x = (6 x 10^-7 m) * (2.5 m) / (5 x 10^-5 m)
= 0.03 m

Therefore, the spacing between the first and second order bright fringes is indeed 0.03 m. The value does not seem too big as it represents the distance between adjacent bright fringes on the screen.

To find the spacing between the first and second order bright fringes for yellow light of wavelength 600nm, you can use the formula x = λL/d, where x is the spacing between fringes, λ is the wavelength of light, L is the distance from the slits to the screen, and d is the distance between the two slits.

Plugging in the given values:

λ = 600nm = 6x10^-7m
L = 2.5m
d = 0.05mm = 5x10^-5m

x = (6x10^-7m)(2.5m) / (5x10^-5m)
= 0.03m

Your calculation is correct. The spacing between the first and second order bright fringes for yellow light with the given parameters is approximately 0.03m. The value of 0.03m does not seem too big; it is a physical distance that represents the separation between consecutive bright fringes on the screen.