find an equation of the line that passess throught 0.-6 amd 5, 3
the slope is (3+6)/(5-0)
Now you have a point and a slope
I am confused on what to do with this?
c'mon, babe. the slope is 9/5, so the line is
Using (0,-6), we get
y = 9/5 x - 6
or, using (5,3)
y = 9/5 (x-5) + 3
which is the same thing.
To find the equation of a line that passes through two given points, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope of the line and b is the y-intercept.
First, we need to find the slope (m). The slope can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Let's label our points:
Point 1: (x1, y1) = (0, -6)
Point 2: (x2, y2) = (5, 3)
Now we can substitute the values into the formula to find the slope:
m = (3 - (-6)) / (5 - 0)
m = 9 / 5
m = 1.8
Now that we have the slope (m), we can proceed to find the y-intercept (b). We can choose either point to substitute into the equation to find b. Let's use Point 1: (0, -6).
y = mx + b
-6 = 1.8 * 0 + b
-6 = b
Now we have our slope (m = 1.8) and y-intercept (b = -6). Therefore, the equation of the line is:
y = 1.8x - 6