Rain is falling vertically down on a car moving at 11 m/s. Tracks made by the raindrops on the side window of the car are inclined 55 degrees with the vertical. Find the speed of the raindrop relative to the ground.

v(rain) = v(car)/ tanα

Can you elaborate more??

To find the speed of the raindrop relative to the ground, we can break down the motion into two components: the vertical component and the horizontal component.

Let's assume that the speed of the raindrop relative to the ground is v_r (in m/s). The vertical component of the raindrop's velocity is v_r * sin(55°) and the horizontal component is v_r * cos(55°).

Now, let's consider the motion of the car. The car is moving at a velocity of 11 m/s horizontally. Since rain is falling vertically, there is no horizontal component of the raindrop's velocity relative to the car.

Therefore, the horizontal component of the raindrop's velocity relative to the ground is the same as the velocity of the car, which is 11 m/s.

Now, we can set up an equation to find the vertical component of the raindrop's velocity relative to the ground. The vertical component of the raindrop's velocity relative to the ground should be equal to the vertical component of the raindrop's velocity relative to the car, which is v_r * sin(55°).

Therefore, we have v_r * sin(55°) = 0.

Since the raindrop is falling vertically, the vertical component of its velocity is not zero. Therefore, v_r must also be equal to 0. This means that the speed of the raindrop relative to the ground is 0 m/s.

So, the speed of the raindrop relative to the ground is 0 m/s.