Math

A model rocket is launched with an initial velocity of 212ft/sec. It's height h, in feet, after t seconds is given by the formula h=212t-16t^2. After how many seconds will the rocket first reach a height of 592ft?

asked by Pam
  1. To get the time, we just substitute h = 592 to the equation:
    h = 212t - 16t^2
    592 = 212t - 16t^2
    16t^2 - 212t + 592 = 0
    4t^2 - 53t + 148 = 0
    Factoring,
    (t - 4)(4t - 37) = 0
    t = 4 s
    t = 37/4 s
    Since it requires the time in which the rocket FIRST reaches a height of 592, we choose the smaller, which is t = 37/4 s.

    Hope this helps :3

    posted by Jai
  2. *lol I'm sorry the smaller time is t = 4s. OMG XD

    posted by Jai

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math

    A model rocket is launched with an initial velocity of 164ft/sec. It's height h, in feet, after t seconds is given by the formula h=164t-16t^2. After how many seconds will the rocket first reach a height of 400ft?
  2. Algebra: Quadratic Functions

    A model rocket is launched with an initial velocity of 128 ft/s from a height of 70 ft. The height of the rocket, in feet, t seconds after it has been launched is given by the function s(t)=−16t^2+128t+70. Determine the time
  3. Algebra

    A model rocket is launched straight upward from the side of a 256-ft cliff. The initial velocity is 96 ft/sec. The height of the rocket h(t) is given by: h(t) =-16t^2+96t+256 where h(t) is measured in feet and t is the time in
  4. calculus

    the height in feet of a rocket from ground level is given by the function f(t)= -16t^2+160t. what is the instantaneous velocity of the rocket 3 seconds after it is launched? A 32 feet/sec B 64 feet/sec C 12 feet/sec D 10 feet/sec
  5. Math

    A model rocket is launched vertically upward so that its height (measured in feet) t sec after launch is given by the following. h(t) = -16t2 + 272t + 8 (a) Find the times when the rocket is at a height of 488 ft. t = sec (smaller
  6. Math

    A model rocket is launched straight upward from the side of a 212-ft cliff. The initial velocity is 86 ft/sec. The height of the rocket h(t) is given by: h(t)=-16t^2+86t+212 where h(t) is measured in feet and t is the time in
  7. Math

    Using h(t)=gt^2+v0t+h0, where g= -16, h0= initial height, v0= initial velocity, and t= time A rocket is fired into the air from the top of a building that is 200 feet tall. The initial velocity of the rocket is 600 feet/sec. If
  8. pre cal

    A toy rocket is launched straight up from the roof of a garage with an initial velocity of 56 feet per second. The height h of the rocket in feet, at t seconds after it was launched, is described by h(t)=−16t2+56t+17. Find
  9. algebra 2

    A model rocket is launched with an initial upward velocity of 164 / ft s . The rocket's height h (in feet) after t seconds is given by the following. = h − 164 t 16 t 2 Find all values of t for which the rocket's height is 92
  10. Math

    A rocket is launched from the top of a 50 foot cliff with an initial velocity of 120 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2 + 120t+ 50. How long after the rocket is launched

More Similar Questions