I would just like someone to check my work and make sure I am doing it correctly before I continue.

f(x)=x^2-3x+5

1. f(2)

I got f(2)=-7

and g(x)=5x-1

1.g(-3)

I got g(-3)=-16

Thanks for any help!!

Wait, does that mean f to the x power or f * x? An you know your supposed to find what F and G are, right?

no

f(2) = 2^2 - 3(2) + 5
= 4 - 6 + 5 = 3

g(-3) = 5(-3) - 1
= -15-1
= -16 --------> you were right with that one

To check if your answers are correct, let's evaluate the given functions at the specified values.

1. To find f(2), substitute x = 2 into the function f(x) = x^2 - 3x + 5:
f(2) = (2)^2 - 3(2) + 5
= 4 - 6 + 5
= 3
Therefore, f(2) = 3, not -7.

2. To find g(-3), substitute x = -3 into the function g(x) = 5x - 1:
g(-3) = 5(-3) - 1
= -15 - 1
= -16
Hence, g(-3) = -16, which matches your answer.

It seems there was an error in calculating f(2). You got -7, but the correct value is 3.
Remember to double-check your calculations to ensure accuracy.