Two airplanes leave St. Louis at the same time and fly in opposite directions. If one travels at 500 kilometers per hour, and the other at 600 kilometers per hour, how long will it take for them to be 1925 kilometers apart?

(500+600)h=1925

500h+600h=1925
1100h=1925
1100h/1100=1925/1100
h=1.77

(500 + 600)h = 1925

Solve for h.

To find out how long it will take for the airplanes to be 1925 kilometers apart, we need to use the formula: Distance = Speed x Time.

Let's calculate the time taken by the first airplane:
Distance = Speed x Time
1925 kilometers = 500 kilometers per hour x Time

Rearranging the formula to solve for Time:
Time = Distance / Speed
Time = 1925 kilometers / 500 kilometers per hour

Time taken by the first airplane = 3.85 hours

Now let's calculate the time taken by the second airplane:
Distance = Speed x Time
1925 kilometers = 600 kilometers per hour x Time

Time = Distance / Speed
Time = 1925 kilometers / 600 kilometers per hour

Time taken by the second airplane = 3.21 hours

Since both airplanes are moving in opposite directions, we need to consider the total time taken by both airplanes. To do that, we will add the individual times together.

Total time taken = Time taken by the first airplane + Time taken by the second airplane
Total time taken = 3.85 hours + 3.21 hours

Total time taken = 7.06 hours

Therefore, it will take approximately 7.06 hours for the airplanes to be 1925 kilometers apart.

To solve this problem, we can use the formula Distance = Speed × Time, where the time is the unknown variable we are trying to find.

Let's denote the time it takes for the airplanes to be 1925 kilometers apart as "t".

The distance traveled by the first airplane is its speed (500 km/h) multiplied by the time (t): 500t.

Similarly, the distance traveled by the second airplane is its speed (600 km/h) multiplied by the time (t): 600t.

Since the two airplanes are flying in opposite directions, the total distance covered by both airplanes is the sum of their individual distances: 500t + 600t.

According to the problem, this total distance is 1925 kilometers. Therefore, we can set up the equation:

500t + 600t = 1925.

Combining like terms:

1100t = 1925.

Now, we can solve for t by dividing both sides of the equation by 1100:

t = 1925 / 1100.

Calculating this gives us:

t ≈ 1.75.

Therefore, it will take approximately 1.75 hours (or 1 hour and 45 minutes) for the two airplanes to be 1925 kilometers apart.