physics
With V = Voe^(t/T), how many time constants does it take for a capacitor to discharge less than 1% of its initial voltage?
asked by
Jason

U =U₀exp(t/T)
U/U₀ =exp(t/T)
ln(U/U₀) = t/T
ln(0.01U₀/U₀) =ln0.01 = t/T
t=Tln0.01=4.61 T
posted by Elena
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