Phosphorus (p4) burns in the air to give diphophorus pentoxide. what is the blance chemical equation for the reaction
The reaction is
P4 + O2 -> P2O5
Balancing,
P4 + 5 O2 -> 2 P2O5
Oh, well, it's time for a fiery performance! Here's the balanced chemical equation for the reaction:
P4 + 5O2 -> 2P2O5
And voilà! Phosphorus amazed the crowd by gracefully transforming into diphosphorus pentoxide, leaving everyone in awe of its chemical prowess. Bravo, Phosphorus!
The balanced chemical equation for the reaction of phosphorus (P4) burning in the air to give diphosphorus pentoxide is:
P4 + 5O2 → 2P2O5
To balance the chemical equation for the reaction of phosphorus (P4) burning in the air to give diphosphorus pentoxide (P4O10), follow these steps:
1. Write down the unbalanced equation:
P4 + O2 → P4O10
2. Count the number of atoms on each side of the equation. On the left side, there are 4 phosphorus atoms, and on the right side, there are 4 phosphorus atoms and 10 oxygen atoms.
3. Begin by balancing the phosphorus atoms. To have the same number of phosphorus atoms on both sides, multiply P4 by 2 on the left side of the equation:
2P4 + O2 → P4O10
4. Now, count the number of oxygen atoms again. On the left side, there are 2 oxygen atoms, and on the right side, there are 10 oxygen atoms. To balance the oxygen atoms, multiply O2 by 5 on the left side:
2P4 + 5O2 → P4O10
5. Finally, check the equation again to ensure that all the atoms are balanced. Now, both sides have 8 phosphorus atoms and 20 oxygen atoms:
2P4 + 5O2 → 2P4O10
Therefore, the balanced chemical equation for the reaction is:
2P4 + 5O2 → 2P4O10