ben has 15 puzzles and 27 cds, when he takes a trip he likes to bring one puzzle and one cd as entertainment. how many trips can he take with a different puzzle and cd pair?? and please show how to solve it.....
With each of the 15 puzzles he can take 27 different CDs
so the number = 15x27 = 405
one more please!! a bike club wants to make license plates for the neighborhood bikes. each license plate has a letter followed by a digit. how many different license plates can be made??? explain please so i can understand how to find the anser THANKS!!!!
Pretend you are making the plate,
How many different letters can you put in the first place ? 26
FOR EACH OF THOSE, how many numbers can you put in the second place ? 10
number of plates = 26 x 10 = 260
To find out how many trips Ben can take with a different puzzle and CD pair, we need to determine the minimum of the two quantities: the number of puzzles (15) and the number of CDs (27).
Since Ben wants to bring one puzzle and one CD for each trip, we'll pair them up. Each pair will consist of one puzzle and one CD.
The number of trips Ben can take is equal to the smaller of the two quantities, which is the minimum of 15 and 27. In this case, it is 15.
Therefore, Ben can take 15 trips with a different puzzle and CD pair each time.
To solve it mathematically, you can use the min() function:
trips = min(15, 27)
The value of "trips" will be 15.