How many milliliters of a 0.5 molar HCl solution are needed to react completely with 15 grams of zinc according to the following equation?

? HCl+? Zn→? ZnCl2 +? H2 Answer in units of mL

Balance the equation first.

mols Zn = grams/molar mass
Using the coefficients in the balanced equation convert mols Zn to mols HCl.
Then M HCl = mols HCl/L HCl. You know M HCl and mols HCl, solve for L HCl and convert to mL.

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To determine the number of milliliters of a 0.5 molar HCl solution needed to react completely with 15 grams of zinc, we need to use stoichiometry. Let's start by balancing the equation:

2 HCl + Zn → ZnCl2 + H2

Now we can see that it takes 2 moles of HCl to react with 1 mole of Zn. First, we need to convert the mass of zinc to moles. The molar mass of Zn is 65.38 g/mol, so:

15 g Zn × (1 mol Zn / 65.38 g Zn) = 0.229 mol Zn

Since the ratio of HCl to Zn is 2:1, we'll need twice as many moles of HCl:

0.229 mol Zn × (2 mol HCl / 1 mol Zn) = 0.458 mol HCl

Finally, we can use the molarity of the HCl solution to determine the volume:

(0.458 mol HCl) / (0.5 mol/L) = 0.916 L = 916 mL

So, you would need 916 mL of the 0.5 molar HCl solution to react completely with 15 grams of zinc.

To determine the number of milliliters of a 0.5 molar HCl solution needed to react completely with 15 grams of zinc, we can use the concept of stoichiometry and the balanced chemical equation.

First, we need to write the balanced chemical equation for the reaction between HCl and zinc (Zn):

2 HCl + Zn → ZnCl2 + H2

From the balanced equation, we can see that it takes 2 moles of HCl to react with 1 mole of Zn. This means the molar ratio between HCl and Zn is 2:1.

Now, let's calculate the number of moles of zinc we have:

Molar mass Zn = 65.38 g/mol

Number of moles Zn = mass / molar mass
= 15 g / 65.38 g/mol
≈ 0.229 mol

Since the molar ratio of HCl to Zn is 2:1, we need twice the number of moles of HCl compared to Zn. Therefore:

Number of moles HCl = 2 * moles Zn
= 2 * 0.229 mol
≈ 0.458 mol

Finally, we can use the molarity of the HCl solution (0.5 M) to determine the volume of the solution required using the equation:

Volume (L) = moles / molarity

Volume (mL) = Volume (L) * 1000

Volume (mL) = 0.458 mol / 0.5 mol/L * 1000
≈ 916 mL

So, approximately 916 milliliters of a 0.5 Molar HCl solution are needed to react completely with 15 grams of zinc.