Find the 7th term of arithmetic progression...12,20,28.

a= 12

d = 8
n = 7
Sn 1/2n[(2a+ (n-1)d)]

7/2[(2*12+ (7-1)8)]
7/2(24+48)

Sn = 7/2(72)

= 252

But, to answer the question,

T7 = 12+6*8 = 60

To find the 7th term of an arithmetic progression, we can use the formula:

an = a1 + (n - 1)d

where:
an = 7th term
a1 = first term
n = position of the term
d = common difference

Given the arithmetic progression is 12, 20, 28, we can determine that:
a1 = 12 (first term)
d = 20 - 12 = 8 (common difference)
n = 7 (position of the term we want to find)

Now, let's substitute these values into the formula:

a7 = 12 + (7 - 1) * 8
= 12 + (6) * 8
= 12 + 48
= 60

So, the 7th term of the arithmetic progression is 60.

To find the 7th term of an arithmetic progression, you can use the formula:

An = A1 + (n - 1)d

where,
An is the nth term of the arithmetic progression
A1 is the first term of the arithmetic progression
n is the position of the term you want to find
d is the common difference between the terms

In this case, the first term (A1) is 12, and the common difference (d) can be found by subtracting the first term from the second term or the second term from the third term, since the common difference is the same between all the terms.

d = (20 - 12) = 8

Now, we can substitute these values into the formula to find the 7th term:
A7 = 12 + (7 - 1) * 8
= 12 + 6 * 8
= 12 + 48
= 60

Therefore, the 7th term of the arithmetic progression 12, 20, 28 is 60.