find the difference when (-2x^2+7x-5) is subtracted from (3x^2-4x+2).
-2x^2+7x-5
- (3x^2-4x+2) so I changed it to
+ (-3x^2+4x-2)
I got -5x^2+11x-7
Is this correct?
3x^2-4x+2
- (-2x^2+7x-5)
3x^2-4x+2
2x^2 -7x +5
=
5x^2 -11x +7
thank you for your help. I guess I put the wrong one on top when I subtracted. I seem to get mixed up which goes first when they ask the wording of the difference.
Thanks for showing me what I did wrong.
Yes, your answer of -5x^2 + 11x - 7 is correct!
To find the difference when (-2x^2+7x-5) is subtracted from (3x^2-4x+2), you need to subtract each term of (-2x^2+7x-5) from their corresponding terms in (3x^2-4x+2).
So, (-2x^2+7x-5) is subtracted from (3x^2-4x+2) as follows:
(3x^2 - 4x + 2) - (-2x^2 + 7x - 5)
When subtracting a term with a negative sign, you need to distribute the negative sign to each term inside the parentheses:
3x^2 - 4x + 2 + (-1 * -2x^2) + (-1 * 7x) + (-1 * -5)
Simplifying this expression, you get:
3x^2 - 4x + 2 + 2x^2 - 7x + 5
Combine like terms:
(3x^2 + 2x^2) + (-4x - 7x) + (2 + 5)
5x^2 - 11x + 7
So the difference when (-2x^2+7x-5) is subtracted from (3x^2-4x+2) is -5x^2 + 11x - 7.