Balance the following equation for a basic solution.
MnO4-+C2O4-2= Mno2 + CO3-2
MnO4 + (C2O4)2 = MnO2 + 2(CO3)2
See your post above.
I disagree with the answer by Ryan.
O doesn't balance
charge on left not same as charge on right
change of electrons doesn't balance.
To balance the given chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Additionally, since the solution is basic, we need to balance the equation in such a way that both the charge and the number of atoms are equal on both sides.
Let's balance the equation step by step:
1. First, let's balance the atoms of Mn. There is one Mn atom on the left side and one on the right side, so it is already balanced.
MnO4- + C2O4-2 = MnO2 + CO3-2
2. Next, let's balance the atoms of C. There are two C atoms on the left side and one on the right side. To balance the C atoms, we can add a coefficient of 2 in front of CO3-2:
MnO4- + C2O4-2 = MnO2 + 2CO3-2
3. Now, let's balance the atoms of O. On the left side, there are 12 oxygen atoms (4 from MnO4- and 8 from C2O4-2), while on the right side, there are 10 oxygen atoms (2 from MnO2 and 8 from 2CO3-2). To balance the oxygen atoms, we can add water (H2O) to the right side of the equation. In this case, since the solution is basic, we should balance the oxygen atoms by adding OH- ions instead of water. Since each OH- ion contains one oxygen atom, we need to add 2 OH- ions:
MnO4- + C2O4-2 = MnO2 + 2CO3-2 + 2OH-
4. Finally, let's balance the charges. On the left side, the MnO4- and C2O4-2 ions have a combined charge of -6, while on the right side, the MnO2, 2CO3-2, and 2OH- ions have a combined charge of -6. So, the charges are already balanced.
The balanced equation for a basic solution is:
MnO4- + C2O4-2 = MnO2 + 2CO3-2 + 2OH-