a student titrated a 1.0115 g sample of potassium hydrogen phthalate (hkc8h4o4 204.2285g/mol with sodium hydroxide. the initial buret reading was 1.16 ml and final reading 40.62 ml write a balanced equation
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To write a balanced equation for this titration reaction, we need to determine the reaction between potassium hydrogen phthalate (KHC8H4O4) and sodium hydroxide (NaOH).
The reaction can be represented as follows:
KHC8H4O4 + NaOH → NaKC8H4O4 + H2O
In this reaction, the potassium hydrogen phthalate (KHC8H4O4) reacts with sodium hydroxide (NaOH) to produce sodium potassium phthalate (NaKC8H4O4) and water (H2O).
Now, let's break down the equation and identify the compounds:
- KHC8H4O4: Potassium hydrogen phthalate (often used as a primary standard in acid-base titrations)
- NaOH: Sodium hydroxide (a strong base)
- NaKC8H4O4: Sodium potassium phthalate (formed during the titration reaction)
- H2O: Water (a product that is formed when an acid reacts with a base)
Please note that the coefficients and state symbols (such as (aq) for aqueous or (s) for solid) may vary depending on the specific conditions and stoichiometry of the reaction.