Factor the Polynomial in quadratic form.
6y(to the sixth power) - 5y(to the third power) - 4
6y^6 - 5y^3 -4
= (2y^3 + 1)(3y^3- 4)
I do not believe the cubic terms are separable into quadratic factors.
To factor the polynomial 6y^6 - 5y^3 - 4, we can follow these steps:
Step 1: Notice that all the terms have a common factor of 1, so we can factor out a 1 from the polynomial to simplify it:
1(6y^6 - 5y^3 - 4)
Step 2: Next, we want to determine if we can factor this polynomial using the quadratic form (ax^2 + bx + c). However, in this case, it is not possible to factor the quadratic terms (y^6 and y^3) into quadratic factors.
Therefore, the polynomial 6y^6 - 5y^3 - 4 cannot be factored further in quadratic form.