Erin is thinking of a 3-digit number.It uses the digits 1,7 and 4.How many numbers can I make that are odd? How many numbers can I make that are even ?Thanks!

If you want an odd number, it cannot end with 4. If you want an even number, it has to end with 4.

Odd:

417
471
741
147

Even:

174
714

Thank you

You're welcome!

To determine the number of odd and even numbers that can be formed using the digits 1, 7, and 4, we need to consider the possible arrangements of these digits.

First, let's determine the total number of possible 3-digit numbers we can form using these three digits. Since repetition is allowed, we have three choices for each digit. So, the total number of possible 3-digit numbers is calculated by multiplying the number of choices for each digit: 3 choices for the first digit, 3 choices for the second digit, and 3 choices for the third digit. Therefore, the total number of 3-digit numbers is 3 x 3 x 3 = 27.

Now, let's consider the number of odd numbers. For a number to be odd, the last digit must be an odd number (1 or 7 in this case). So, we have 2 choices for the last digit. The remaining 2 digits can be any arrangement of the remaining 2 digits (1 and 7) including repetition. So, the number of odd numbers is calculated by multiplying the choices for each digit: 2 choices for the last digit, 3 choices for the first digit, and 2 choices for the second digit (since we have already used one digit). Therefore, the number of odd numbers is 2 x 3 x 2 = 12.

To determine the number of even numbers, we need to subtract the number of odd numbers from the total possible numbers. So, the number of even numbers is calculated as: Total possible numbers - Number of odd numbers = 27 - 12 = 15.

Therefore, there are 12 odd numbers and 15 even numbers that can be formed using the digits 1, 7, and 4.