is there even a solution to this problem:
x^2 − 10x + 20 = 0
I think this answer is no solution , please confirm I am right...
The discriminant is 100-80 = 20 > 0, so there are two real solutions. But it contains square roots. Use the quadratic formula.
do I use the discrimate of b^2-4ac
I meant to say discriminate but yet I am confused..
x = 5 +/- Sq root 5?
i'm i right?
x=5+/- sq root of 5?
To determine if there is a solution to the equation x^2 − 10x + 20 = 0, we can use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Comparing the equation x^2 − 10x + 20 = 0 to the general quadratic form ax^2 + bx + c = 0, we can identify that a = 1, b = -10, and c = 20.
Plugging these values into the quadratic formula, we have:
x = (-(-10) ± √((-10)^2 - 4(1)(20))) / (2(1))
x = (10 ± √(100 - 80)) / 2
x = (10 ± √20) / 2
x = (10 ± √(4 * 5)) / 2
x = (10 ± 2√5) / 2
x = 5 ± √5
So, the two solutions to the equation x^2 − 10x + 20 = 0 are x = 5 + √5 and x = 5 - √5.
Therefore, your initial assessment that there are no solutions to the equation is incorrect. There are indeed two solutions.