Al(NO3)3+ NaCl
How about
Al(NO3)3+ 3NaCl = AlCl3 + 3NaNO3
The chemical reaction between Al(NO3)3 (aluminum nitrate) and NaCl (sodium chloride) is a double displacement reaction. In this type of reaction, the positive ions in one compound switch places with positive ions in the other compound.
To determine the products of this reaction, we need to identify the positive ions in each compound. Aluminum nitrate (Al(NO3)3) contains the aluminum ion (Al3+) and the nitrate ion (NO3-). Sodium chloride (NaCl) contains the sodium ion (Na+) and the chloride ion (Cl-).
During the reaction, the aluminum ion (Al3+) from aluminum nitrate will combine with the chloride ion (Cl-) from sodium chloride to form aluminum chloride (AlCl3). The sodium ion (Na+) from sodium chloride will combine with the nitrate ion (NO3-) from aluminum nitrate to form sodium nitrate (NaNO3).
So, the complete equation for the reaction between Al(NO3)3 and NaCl is:
Al(NO3)3 + 3NaCl → AlCl3 + 3NaNO3