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Find the second derivative of the following function: y=log(base2)x/x² y'=[(x/ln2)2xlog(base2)x]/x^4 the derivative of x/ln2 is (ln2)^1? y"={[((ln2)^(1))(2log(base2)x/xln2)]x^44x³[(x/ln2)2xlog(base2)x]}/x^8 I tried
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Did I do this correctly? Use log laws to write the following expression as a single logarithm. 3/2 ln25 + 3 ln2 = ln25 3/2 + ln2^3 = ln125 + ln2^3 =ln125 + ln8 =ln(125*8) =ln1000
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Did I do this correctly? Use log laws to write the following expression as a single logarithm. 3/2 ln25 + 3 ln2 = ln25 3/2 + ln2^3 = ln125 + ln2^3 =ln125 + ln8 =ln(125*8) =ln1000
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