How would you find x and y?
[2x 1] [1 3] [-4 -9]
=
[2 0] [2 -y] [2 6]
Not familiar with that notation. What is being equated?
Hmmm.
If you want to multiply matrices
[2x 1]
[2 0]
and
[1 3]
[2 -y]
then the result is
[2x+2 6x-y]
[2 6]
and we need
2x+2 = -4
6x-y = -9
so
(x,y) = (-3,-9)
wolframalpha.com can help with this kind of stuff.
To see the product of the matrices, just enter
{{2x,1},{2,0}}*{{1,3},{2,-y}}
To see the actual solution, enter
solve {{2x,1},{2,0}}*{{1,3},{2,-y}} = {{-4,-9},{2,6}}
To find the values of x and y in the given system of equations, we can use the method of matrix multiplication. Let's set up the equation using matrices:
[2x 1] [1 3] [-4 -9]
=
[2 0] [2 -y] [2 6]
The equation can be written as:
⎡2x + 1 6x + 3⎤ ⎡-4 -9⎤
=
⎣2 -2y⎦ ⎣2 6⎦
Now, we can equate the corresponding elements of the matrices and form a system of equations:
2x + 1 = -4
6x + 3 = -9
2 = 2
-2y = 6
Simplifying the equations, we get:
2x = -5
6x = -12
2 = 2
y = -3
Now, let's solve for x and y:
From the first equation, we can find the value of x:
2x = -5
x = -5/2
From the second equation, we can find the value of x again:
6x = -12
x = -12/6
x = -2
Since both values of x are different, there is no solution for this system of equations.