The fizz produced when an alka-seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate and citric acid:

3NaHCO3 + H3C6H5O7 -> 3CO2 + 3H2O + Na3C6H5O7

In an Experiment 1.00 g of sodium bicarbonate and 1.00g of citric acid are allowed to react?

1.) what volume of carbon dioxide is formed ?

determine the moles of citric acid and bicarbonate from the masses.

You need 3x more mole of bicarbonate than moles of cirtic acid?

a. Assume it works out 4.2 moles bicarobante to each citric acid mole...you have too much bicarbonate. So you will be limited by the citric acid. Moles of carbon dioxide=3 x moles of cirtic acid.

b. assume it works out you have 2.5 moles of bicarbonate to each mole of citric acid. Then you are limited by the bicarbonate...moles of carbon dioxide will equal same moles as bicarbonate.

Think on this.

Then change moles of CO2 to volume, assume STP, as stupid as that is. Or you could assume room temperature. Whatever.

To find the volume of carbon dioxide (CO2) formed in the reaction, we need to use the ideal gas law. The ideal gas law formula is:

PV = nRT

Where:
P = pressure of the gas
V = volume occupied by the gas
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin

In this case, we are given the mass of the reactants (sodium bicarbonate and citric acid), so we need to calculate the number of moles of each reactant first, and then determine the limiting reactant.

Let's start with calculating the moles of sodium bicarbonate (NaHCO3) and citric acid (H3C6H5O7) using their molar masses.

1 mole of NaHCO3 weighs 84.01 g/mol
1 mole of H3C6H5O7 weighs 192.12 g/mol

Moles of NaHCO3 = mass of NaHCO3 / molar mass of NaHCO3
Moles of NaHCO3 = 1.00 g / 84.01 g/mol

Moles of H3C6H5O7 = mass of H3C6H5O7 / molar mass of H3C6H5O7
Moles of H3C6H5O7 = 1.00 g / 192.12 g/mol

Now, let's compare the moles of each reactant to determine the limiting reactant. The reactant that is completely consumed or used up first is the limiting reactant.

To do this, we need to calculate the mole ratio of the reactants based on the balanced chemical equation:

3NaHCO3 + H3C6H5O7 -> 3CO2 + 3H2O + Na3C6H5O7

According to the equation, the mole ratio of NaHCO3 to H3C6H5O7 is 3:1 (3 moles of NaHCO3 for every 1 mole of H3C6H5O7).

Now, let's compare the moles of NaHCO3 and H3C6H5O7:

Moles of NaHCO3 / 3 = moles of H3C6H5O7 / 1

If the moles of NaHCO3 divided by 3 are less than the moles of H3C6H5O7 divided by 1, then NaHCO3 is the limiting reactant. Otherwise, H3C6H5O7 is the limiting reactant.

Once you determine the limiting reactant, you can use its mole ratio from the balanced equation to calculate the moles of CO2 produced:

moles of CO2 = moles of limiting reactant * (3 moles of CO2 / 3 moles of limiting reactant)

Now, to find the volume of CO2, we can use the ideal gas law formula:

V = (moles of CO2 * R * T) / P

The pressure (P) and temperature (T) will depend on the conditions of the reaction. Make sure to convert the temperature to Kelvin (add 273.15 to the temperature in Celsius) before using it in the equation.

Once you have the volume in liters, you can convert it to other units, if necessary.

Remember to include units throughout the calculations and substitutions to ensure accurate results.