If a 14N force is used to compress a spring with a spring constant of 5.0×102N/m , what is the resulting spring compression?
the spring compresses until the spring force equals the applied force
14 N = x * 5.0×10^2 N/m
To find the resulting spring compression, we can use Hooke's Law, which states that the force exerted on a spring is proportional to its displacement. The formula for Hooke's law is:
F = -k * x
Where F is the force applied to the spring, k is the spring constant, and x is the displacement or compression of the spring.
In this case, we have a force of 14N and a spring constant of 5.0×10^2 N/m.
Plugging these values into the formula, we can solve for x:
14 = - (5.0×10^2) * x
To isolate x, we divide both sides of the equation by -5.0×10^2:
14 / (-5.0×10^2) = x
x = -0.028 m
Therefore, the resulting spring compression is -0.028 meters. Note that the negative sign indicates the compression of the spring rather than an extension.