A spring has a spring constant of 25N/m .
Part A
How much work is required to stretch the spring 2.0cm from its equilibrium position?
w = 1/2 k x^2
where x is the distance stretched
No ans
To calculate the work required to stretch the spring, we can use the formula for work done by a spring:
Work = (1/2) * k * x^2
where:
k is the spring constant (given as 25 N/m)
x is the displacement from the equilibrium position (given as 2.0 cm or 0.02 m)
Now, let's substitute the given values into the formula and evaluate the result:
Work = (1/2) * 25 N/m * (0.02 m)^2
= (1/2) * 25 N/m * 0.0004 m^2
= (1/2) * 0.01 N * m
= 0.005 N * m
Therefore, the work required to stretch the spring 2.0 cm from its equilibrium position is 0.005 N * m.
To calculate the work required to stretch the spring, you can use the formula:
Work = (1/2) * k * x^2
Where:
- Work is the amount of work required (in joules)
- k is the spring constant (in newtons per meter)
- x is the displacement from the equilibrium position (in meters)
First, convert the displacement from centimeters to meters:
2.0 cm = 2.0 / 100 = 0.02 meters
Now, plug in the values into the formula:
Work = (1/2) * 25 N/m * (0.02 m)^2
Solving the equation:
Work = (1/2) * 25 N/m * 0.0004 m^2
Work = 0.5 * 25 N/m * 0.0004 m^2
Work = 0.5 * 0.01 Nm
Work = 0.005 Nm
Therefore, the work required to stretch the spring 2.0 cm from its equilibrium position is 0.005 joules (or Nm).