If the molar concentration of sodium ions is 0.44 M, then the concentration of sodium sulfate is 0.88 M
True or False
I assume you are to calculate this to know if it is true or false.
Na2SO4 ==> 2Na^+ + SO4^2-
0.44M Na^+ x (1 mol Na2SO4/2 mols Na) = 0.44 x 1/2 = ?
False.
To determine the concentration of sodium sulfate, we need to understand its chemical formula and the stoichiometry of the reaction between sodium ions and sulfate ions.
The chemical formula for sodium sulfate is Na2SO4. This means that for every 1 mole of sodium sulfate, we have 2 moles of sodium ions (Na+) and 1 mole of sulfate ions (SO4^2-).
Given that the molar concentration of sodium ions is 0.44 M, we can conclude that the molar concentration of sodium sulfate is equal to half of that, or 0.22 M. This is because for every mole of sodium ions, we need half a mole of sodium sulfate to react and form 2 moles of sodium ions.
Therefore, the correct statement would be: If the molar concentration of sodium ions is 0.44 M, then the concentration of sodium sulfate is 0.22 M.