What maximum height will a 318.3 m driver each if it is launched at an angle of 17.0� tothe ground? The acceleration due to gravityis 9.81 m/s2.
To find the maximum height reached by a projectile, we can use the equations of motion. In this case, we are given the initial velocity (318.3 m/s), launch angle (17.0 degrees), and acceleration due to gravity (9.81 m/s²).
First, we'll need to find the vertical component of the initial velocity. The vertical component of the velocity (Vy) can be determined using the equation:
Vy = Vo * sin(theta)
where Vo is the initial velocity and theta is the launch angle. Let's calculate Vy:
Vy = 318.3 m/s * sin(17.0 degrees)
Vy = 88.18 m/s
Now, we can use this vertical component of velocity to find the maximum height (H) reached by the driver. The formula to find the maximum height is:
H = (Vy^2) / (2 * g)
where g is the acceleration due to gravity. Let's calculate H:
H = (88.18 m/s)^2 / (2 * 9.81 m/s²)
H = 397.3 m
Therefore, the maximum height reached by the driver is approximately 397.3 meters.