can someone help me with this and explain it to me step by step so i can try to solve the remaining problems i have I have no idea of what I am supposed to do
For each problem, construct two composite functions, . Evaluate each composite function for x=2.
f(x)=x^3-4x^2-x+4 How do I find the x-intercept for this? This is from my book: step 1: 0=x^3-4x^2-x+4 step 2: 0=x^2(x-4)+(-1)(x-4) step 3: 0=(x^2-1)(x-4) I know how to solve once I get to step 3, but in step 2, I don't know what
I need help solving the problem not the answer. (Multiple Choice) The steps below show the incomplete solution to find the value of x for the equation 7x + 8 − 3x = −6 + 10: Step 1: 7x + 8 − 3x = −6 + 10 Step 2: 7x + 8 −
I am currently doing a question in which the equation is dN1/dt= -N1 + 0.1N1*N2 However, I am able to follow until the step of -N1(1 - 0.1N2) after that I'm not able to follow to the step of (-1)N1 (1-N2/10) Can someone please
In which step is the error? Step 1: Let x = 1 and y = 1. Step 2: By substitution xy = y^2. Step 3: Multiplying both sides by -1, -xy= -y^2. Step 4: Adding x^2 to both sides, x^2-xy=x^2-y^2. Step 5: Factoring, x(x-y)=(x+y)(x-y).
In a chain mechanism, a reaction in which two free radicals combine to form a stable molecule would be called the A) initiation step B) termination step C) propagation step D) inhibition step E) branching step
In which step below does a mistake first appear in simplifying the expression? 0.5(-12c+6)-3(c+4)+10(c-5) Step 1: -6c+3-3(c+4)+10(c-5) Step 2: -6c+3-3c-12+10(c-5) Step 3: -6c+3-3c-12+10c-50 Step 4: 7c-41 Please help me!!! Thank
Al2(s04)3 solution of 1 molal concentration is present in 1 litre solution of 2.684g/cc.How many moles of bas04 would be precipitation on adding bacl2 in excess? The answer 6M I do not understand pls explain step by step Thank a
10a) Simplify the expression and explain each step. 12 + 3(2y – 3) Step 1: apply distributive property Step 2: combine like terms Step 3: simplify b) Factor the expression completely. 18b – 12 What is the GCF of 18 and 12? Use