I need help to create an addition word problem and a subtraction word problem using fractions. I need to show how to find the solution to each problem. Once I find the solutions to my problems, I have to rewrite the solutions as either a terminating or nonterminating decimal.
During the morning, Marissa drank 3/4 glass of orange juice, 1/8 glass of prune juice, and 1/2 glass of milk. How much did she drink all together?
James had 2 cups of raisins. He put 1/4 cup on his cereal. Then he ate 5/8 cup. Finally he put 1 1/16 cup in oatmeal raisin cookies. How much raisins did he have left?
Thank you for your help Ms. Sue, It's greatly appreciated ^-^
You're very welcome.
Sure! Let's start with an addition word problem using fractions. Here's an example:
Problem: Mary had 3/4 of a pizza, and John had 1/2 of a pizza. How much pizza did they have together?
To solve this problem, we need to find a common denominator for the fractions. In this case, the common denominator is 4.
Step 1: Convert the fractions to have a common denominator:
3/4 + 1/2 = 6/8 + 4/8
Step 2: Add the fractions together:
6/8 + 4/8 = 10/8
Step 3: Simplify the fraction, if possible:
10/8 simplifies to 5/4
Solution: Mary and John had 5/4 of a pizza together.
To rewrite this solution as a decimal, divide the numerator (5) by the denominator (4):
5 ÷ 4 = 1.25
So, the solution can be written as a terminating decimal: 1.25.
Now, let's move on to a subtraction word problem using fractions.
Problem: Lisa had 5/6 of a cake, and she gave 2/3 of it to her friend. How much cake does she have left?
To solve this problem, we'll subtract the fraction that was given away from the original fraction.
Step 1: Convert the fractions to have a common denominator:
5/6 - 2/3 = 5/6 - 4/6
Step 2: Subtract the fractions:
5/6 - 4/6 = 1/6
Solution: Lisa has 1/6 of the cake left.
To rewrite this solution as a decimal, divide the numerator (1) by the denominator (6):
1 ÷ 6 ≈ 0.1667
So, the solution can be approximated as a nonterminating decimal: 0.1667.
I hope this helps! Let me know if you have any further questions or need more assistance.