College Algebra

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-1, 1/8); vertical axis.

There is no focus of the parabola or equation given, so how am I suppose to solve this problem?

  1. 0
asked by Joy
  1. see the other solution I gave.
    Same exact problem, just a different point.

    posted by Steve
  2. V(0,0), P(-1,1/8).

    Y = a(x-h)^2 + k.
    1/8 = a(-1-0)^2 + 0.
    a = 1/8.

    Y = 1/8(x-0)^2 + 0.
    Y = (1/8)x^2.

    posted by Henry

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