Assuming all volume measurements are made
at the same temperature and pressure, what
volume of hydrogen gas is needed to react
completely with 2.96 L of oxygen gas to pro-
duce water vapor?
Answer in units of L
I thought you were working these the last day or so like a pro. What's the problem with this?
I was not working on these the other day. I think I might know how to do this problem, but can you explain it so i can be sure?
Yes I can; however, if you thought about it, it would be easier for you to show what you did and let me check it. That way I can see if you are doing anything wrong. However, just this once.
2H2 + O2 ==> 2H2O
When everything is in the gaseous state we may use L as if volume = mols.
Therefore, 2.96L x (1 mol O2/2 mols H2) = 2.96 x 1/2 = 1.48 L O2 needed.
I thought you were supposed to multiply 2.96 by 2 to get 5.92L. Why would you multiply it by .5 when you are trying to find out the volume of hydrogen gas?
Because I worked it wrong. I read the problem as having H2 and asking how much oxygen and not how much H2. I already had volume O2.
2.96 L O2 x (2 mol H2/1 mol O2) = 2.96 x 2 = ?
Sorry about that.
Thank you
To determine the volume of hydrogen gas needed to react completely with oxygen gas, we need to use the balanced chemical equation for the reaction. In this case, the equation is:
2 H₂ + O₂ → 2 H₂O
From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water vapor.
Step 1: Convert the given volume of oxygen gas to the number of moles.
To do this, we need to use the ideal gas law:
PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L×atm/mol×K), and T is the temperature (assuming constant).
Given:
Volume of oxygen gas (V) = 2.96 L
Since the temperature and pressure are not mentioned, we can assume they are constant. Therefore, we can omit them from the equation.
Step 2: Convert moles of oxygen gas to moles of hydrogen gas.
From the balanced chemical equation, we know that 2 moles of hydrogen gas react with 1 mole of oxygen gas. So, we can set up a ratio:
2 moles of H₂ / 1 mole of O₂
Step 3: Convert moles of hydrogen gas to volume.
Finally, we can convert the moles of hydrogen gas to volume using the ideal gas law again.
V = (n × R × T) / P
Given:
Pressure (P) = constant
Temperature (T) = constant
Since both the temperature and pressure are constant, we can simplify the formula to:
V = n × R / P
Step 4: Calculate the volume of hydrogen gas.
Using the above formula and the ratio derived from the balanced chemical equation, we can calculate the volume of hydrogen gas.
Volume of hydrogen gas = (2 moles of H₂ / 1 mole of O₂) × (2.96 L of O₂)
Volume of hydrogen gas = (2 moles of H₂ / 1 mole of O₂) × (2.96 L of O₂) / (1 mole of H₂)
The final volume will be in liters (L). Calculate the value using the above formula to obtain the answer.