A certain personality index postulated by Professor Bailey is normally distributed, with a mean of 0.4 and a variance of 0.0004. What is the probability that the Professor Bailey’s personality index of a randomly selected person will exceed 0.44?
Z = (score-mean)/SD
variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.