At a pet store, Rhonda paid $11.50 for 3 dog bowls and 4 bones. Kelly paid $13 for 2 dog bowls and 8 bones. How much will Andrew pay for 4 dog bowls and 2 bones?
To find out how much Andrew will pay for 4 dog bowls and 2 bones, we can start by determining the cost of each dog bowl and bone separately.
To do this, we can divide the total amount paid by the number of dog bowls and bones purchased.
For Rhonda:
Total cost = $11.50
Number of dog bowls = 3
Number of bones = 4
Cost per dog bowl = Total cost / Number of dog bowls = $11.50 / 3 = $3.83 (rounded to the nearest cent)
Cost per bone = Total cost / Number of bones = $11.50 / 4 = $2.88 (rounded to the nearest cent)
For Kelly:
Total cost = $13
Number of dog bowls = 2
Number of bones = 8
Cost per dog bowl = Total cost / Number of dog bowls = $13 / 2 = $6.50
Cost per bone = Total cost / Number of bones = $13 / 8 = $1.63 (rounded to the nearest cent)
Now we can calculate the cost for Andrew:
Number of dog bowls = 4
Number of bones = 2
Cost for 4 dog bowls = Cost per dog bowl * Number of dog bowls = $6.50 * 4 = $26.00
Cost for 2 bones = Cost per bone * Number of bones = $1.63 * 2 = $3.26 (rounded to the nearest cent)
Therefore, Andrew will pay $26.00 for 4 dog bowls and $3.26 for 2 bones, making a total of $29.26.
If
A = 3d+4b = 11.50
B = 2d+8b = 13.00
4d+2b = 7/4 A - 5/8 B = 7/4 * 11.50 - 5/8 * 13.00 = 12.00