a car is traveling at a speed of 30.0m/s encounters an emergency and comes to complete stop how much time will it take for the car to stop if it decelerates -4.o m/s^2
To find the time it takes for the car to stop, we can use the equation of motion:
vf = vi + at
Where:
vf = final velocity (0 m/s, since the car comes to a complete stop)
vi = initial velocity (30.0 m/s)
a = acceleration (-4.0 m/s^2)
t = time
Substituting the given values into the equation, we get:
0 = 30.0 + (-4.0)t
Rearranging the equation:
-4.0t = -30.0
Dividing both sides by -4.0:
t = -30.0 / -4.0
Simplifying the equation:
t = 7.5 seconds
Therefore, it will take 7.5 seconds for the car to come to a complete stop.
To find the time it takes for the car to come to a complete stop, you can use the equation:
v = u + at
Where:
v = final velocity (0 m/s, as the car comes to a complete stop)
u = initial velocity (30.0 m/s)
a = acceleration/deceleration (-4.0 m/s^2)
t = time
Rearranging the equation to solve for time:
t = (v - u) / a
Substituting the given values:
t = (0 - 30.0) / -4.0
Simplifying:
t = -30.0 / -4.0
Dividing -30.0 by -4.0:
t = 7.5 seconds
Therefore, it will take the car 7.5 seconds to come to a complete stop.
V = Vo + a*t = 0
30 - 4*t = 0
-4t = -30
t = 7.5 s.
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