The speed of a moving sidewalk at an airport is 2ft/sec. A person can walk 93ft forward on the moving sidewalk in the same time it takes to walk 12ft on a non moving sidewalk in the oppsite direction. At what rate would a person walk on a nonmoving sidewalk?

let man's walking speed be x ft /s

so speed with moving sidewalk = x+2 ft/s

time taken to walk 93 ft on moving sidewalk
= 93/(x+2)
times taken to walk 12 ft in opposite direction
= 12/(x-2)

93/(x+2) = 12/(x-2)
93x - 186 = 12x + 24
81x = 210
x = 210/81 ft/s = 70/27 or appr 2.59 ft/sec

check:
time to walk 93 ft at 4.59 ft/sec = 93/4.59 = 20.26 sec
time to walk 12 ft at .59 ft/sec = 20.3 sec
small error due to round-off
Answer is correct.

Thank you so much.

24/81

To find the rate at which a person would walk on a non-moving sidewalk, we can set up a proportion using the information given.

Let's assume that the rate at which the person would walk on a non-moving sidewalk is represented by "x" ft/sec.

On the moving sidewalk, the person walks 93ft in the same time it takes to walk 12ft on the non-moving sidewalk in the opposite direction. This means that the time taken for both distances is the same.

Time taken to walk 93ft on the moving sidewalk = Time taken to walk 12ft on the non-moving sidewalk in the opposite direction

Distance/Speed = Time

93ft / (2ft/sec) = 12ft / x ft/sec

Now, we can cross-multiply and solve for x:

93(x ft/sec) = 12(2 ft/sec)

93x = 24

x = 24/93 ≈ 0.258 ft/sec

Therefore, a person would walk at a rate of approximately 0.258 ft/sec on a non-moving sidewalk.