Victor drove his truck off a cliff that was 45m high, and it landed 35m from the base of the cliff. What was the velocity of the truck as it drove off the cliff?
h = Vo*t + 0.5g*t%2 = 45 m.
h = 4.9t^2 = 45
t^2 = 9.18
Tf = 3.03 s. = Fall time.
Dist. = Xo * Tf = 35 m.
Xo * 3.03 = 35
Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.