In the space below, show your work for determining the volume, mass, and moles of baking soda

Moles of baking soda reacted
Mass of baking soda reacted (g)
Volume of baking soda reacted

140 ml of vinegar

5 tsps of baking soda were used

You don't provide enough information to answer any of these except volume baking soda is 5 tsps.

Volume of sample (mL) 100ml

Mass of sample (g) 100g

Density (g/mL) 1g/ml

To determine the volume, mass, and moles of baking soda reacted, we need to follow a series of steps:

1. Convert the volume of vinegar from milliliters (ml) to liters (L).
140 ml * (1 L / 1000 ml) = 0.14 L

2. Determine the molar mass of baking soda (sodium bicarbonate, NaHCO3).
The molar mass can be calculated by summing the atomic masses of its constituent elements:
Na (sodium) = 22.99 g/mol
H (hydrogen) = 1.01 g/mol
C (carbon) = 12.01 g/mol
O (oxygen) = 16.00 g/mol
NaHCO3 = 22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.01 g/mol

3. Convert the teaspoons (tsps) of baking soda to grams (g). This conversion requires the density of baking soda, which is approximately 2.19 g/cm³.
5 tsps * (4.93 g / tsp) = 24.65 g

4. Calculate the moles of baking soda reacted using the equation:
moles = mass / molar mass
moles = 24.65 g / 84.01 g/mol ≈ 0.293 mol

5. There is no direct method to determine the volume of baking soda reacted without additional information. The volume of vinegar is given, but it does not solely represent the volume of baking soda reacted because there may be differences in their densities.